four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber
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Answer:
first term =5
common difference=1
Step-by-step explanation:
let the numbers in the AP as a-3d, a-d, a+d, a+3d
according to the question
(a-3d) +(a+3d)=10
2a=10
a=10/2=5-) (1)
and (a-d) (a+d) =24
a2-d2=24
from (1) we get 52-d2=24
d2=25-24
=√1=1
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