four numbers are in AP whose sum is 20 and sum of their squares is 180 .Find numbers
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Step-by-step explanation:
Four numbers are in A.P. therefore the terms are :
a-3d,a-d,a+d,a+3d .
Given,
The sum of the term is =20
Sum of the squares of number is =180
By first condition,
So (a-3d)+(a-d)+(a+d)+(a+3d) =20
4a =20
a=5
By 2nd condition,
(a-3d)²+(a-d)²+(a+d)²+(a+3d)² =180
Substitute the value of a and solve the equation
100+20d²=180
20d²=180–100
d²=80/20
d²=4
d=2 or d=-2
Case 1: a=5 d=2
a-3d= -1 and a-d= 3
a+3d= 11 and a+d= 7
Case 2: a=5 , d=-2
a-3d= 11 and a-d= 7
a+3d= -1 and a+d= 3
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hello
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i hope it will help you. shreya
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