Question

Four numbers are in the ratio of 11: 15: 9: 23. If the sum of the largest and the smallest equals to 4160 then what will be the average of these numbers?

Answer 1

Step-by-step explanation:

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Answer 2

Given,

Ratio of four numbers = 11:15:9:23

Sum of the largest and smallest numbers = 4160

To find,

The average of these numbers.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the four numbers = 11x , 15x , 9x and 23x

(obtained from the ratio of 11:15:9:23 and x is an assumed variable.)

So,

The smallest number = 9x

The largest number = 23x

Their sum = (23x + 9x) = 32x

According to the data mentioned in the question,

32x = 4160

x = 4160/32

x = 130

So,

The first number is = 11x = 11×130 = 1430

The second number is = 15x = 15×130 = 1950

The third number is = 9x = 9×130 = 1170

The fourth number is = 23×130 = 2990

Now,

Their sum = 1430+1950+1170+2990 = 7540

As, there are four (4) numbers,

So, Their average will be = Their sum ÷ 4 = 7540÷4 = 1885

Hence, their average will be 1885