Question

Four numbers are in the ratio of 11: 15: 9: 23. If the sum of the largest and the smallest equals to 4160 then what will be the average of these numbers?​

Answer 1

Answer:

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Answer 2

Given:

Four numbers are in the ratio of 11: 15: 9: 23.

To find:

what will be the average of these numbers?

Solution:

Let the numbers be

11x, 15x, 9x, 23x.

Largest number = 23x

Smallest number = 9x

We know that

sum of the largest and the smallest equals to 4160

So we get

$23x+9x=4160\\32x=4160\\x=4160/32\\x=130$

The given numbers are:

23x, 11x, 9x, 15x

So substitute the value of x to get the real numbers

So we get

$23x=23(130)\\2990\\15x=15(130)\\1950\\11x=11(130)\\1430\\9x=9(130)\\1170$

So now we will find the average of these numbers

So we get

$=(2990+1950+1430+1170)/4\\=1885$

Hence, we get the average of these numbers is 1885.