Four numbers in the ratio 1:3:4:7 add upto give a sum of 105 find the value of the biggest number
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3
The greatest number will be the one with the ratio of 7.
Since there is a total of (1+3+4+7) = 15 sections, the greatest number must be:
7/15 × 105
= 49
Since there is a total of (1+3+4+7) = 15 sections, the greatest number must be:
7/15 × 105
= 49
Answered by
0
let the no.are X,3X,4X,7X.now,X+3X+4X+7x=105,15X=105,X=105÷15,X=7,biggest no. is 7X is49
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