Four object A, B ,C and D of masses 5kg ,10kg , 15kg and 20kg respectively, are moving with same velocity. Which of these has the least momentum?
Answers
Answered by
1
Answer:
Consider object of masses 10kg and 20 kg as A and B object A,
Mass of object A,
m
1
=10kg
Initial velocity of object A, u
1
=10ms
−1
Final velocity of A, v
1
=12ms
−1
Mass of object B, m
2
=20kg
Initial velocity of object B, u
2
=5ms
−1
Final velocity of B, v
2
=4ms
−1
Formula F=
t
m(v−u)
For object A, F
1
=
t
m
1
(v
1
−u
1
)
F
1
=
2
10(12−10)
=10N
For object B, F
2
=
t
m
2
(v
2
−u
1
)
F
2
=
2
20(4−5)
=−10N
As F
1
=10N and F
2
=−10N which proves Newton's third law of motion (i.e,) conservation of momentum
Similar questions