Question

four objects are placed at four different corners as shown in the image given below the gravitational force between which two object will be maximum​

Answer 1

Question :

An object travels 20m in 4s and then other 20m in 10s . What is the average speed of the object ?

Solution :

As per the question we have two cases so let's assume each as Case 1 and Case 2 respectively !

Case 1 :

Distance Covered : 20m

Time taken : 4 sec

Speed : Distance / time

: 20 / 4

: 5 m / sec

Case 2 :

Distance Covered : 20 m

Time taken : 10 sec

Speed : Distance / time

: 20 / 10

: 2 m / sec

\huge \sf \: average \: speed = \frac{total \: distance}{total \: time}averagespeed=totaltimetotaldistance

= \frac{5 + 2}{4 + 10}=4+105+2

= \frac{7}{40} = 0.175=407=0.175

Hence , the average speed of the object is 0.175 m / sec !!