Question

Four of the interior angles of a hexagon are 128°.
The other two angles are equal. How large are the other
two angles?

Answer 1

Answer:

104°

Step-by-step explanation:

Sum of the interior angles of a hexagon = (n-2) 180°

Where n is number of sides i.e. 6

(6-2)180°=720°

One angle = 128

Four angles = 128*4=512

Let one angle be x

Two angles =2x

Therefore , 2x + 512° = 720°

2x= 720°-512°=208°

X = 208°/2=104°

Hence both angles meauser 104°

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