Physics, asked by praveensaini5678, 9 months ago

Four particles A, B, C and D of masses m, 2 m,
3 m and 4 m respectively are placed at corners of
a square of side x ​

Answers

Answered by Anonymous
2

Answer:

Explanation:

Taking A as origin, co-ordinates of A(0,0),B(x,0),C(x,x),D(0,x)

xcm=m×0+2m×x+3m×x+4m×0m+2m+3m+4m=x2

ycm=m×0+2m×0+3m×(x)+4m×(x)m+2m+3m+4m

=710x

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