Question

Four particles are located at the vertices of a square of side d. They all start moving simultaneously with a constant speed v, but they move in such a way that the first particle is continually headed for the second, the second for the third, the third for the fourth, and the fourth for the first. When will they collide?

Answer 1

Hi U study in Vidyamandir?

U are in which branch?

Answer 2

Answer:

Here, as in the question the 4 particles are moving simultaneously behind each other for a n sided polygon separated by a distance d. Then we use the formulae to find the time at which they will meet.

[/tex]t=\frac{d}{v(1-cos\frac{2pie}{n}) }[/tex].

Where t is the time of meeting, v is the velocity of the approach of particles.

So, as in this case it is a square then n=4.

[/tex]t=\frac{d}{v(1-cos\frac{2pie}{4}) }[/tex].

[/tex]t=d/v(As cos90 is zeo).