Four particles each of mass 2 kg are kept at the four corners of a square of edge length 2 m. The moment of inertia of the system about an axis which is perpendicular to the plane of the square and passing through centre of square is
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Answered by
1
Answer:The perpendicular distance of every particle from the given line is a/
2
. The moment of inertia of one particle is, therefore, m(a/
2
)
2
=
2
1
ma
2
. The moment of ineria of the system is, therefore
4×
2
1
ma
2
=2ma
2
Explanation:by this you can find.
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Answered by
3
Answer:
hi mate your answer is here
Explanation:
2ma
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