Four particles each of mass m are kept at the four vertices of a square of side 'a' . Find graitational potential energy of this system.
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-Gmm/r*4+-Gmm/√2r*2
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gravitational potential energy of this system = Gm²/a [4 + √2]
ABCD is square of side length a in which four particles each of means m are kept at the four vertices.
gravitational potential energy of this system = G.P.E between A and B + G.P.E between B and C + G.P.E between C and D + G.P.E between D and A + G.P.E between A and C + G.P.E between B and D
= Gmm/a + Gmm/a + Gmm/a + Gmm/a + Gmm/√2a + Gmm/√2a
= 4Gm²/a + √2Gm²/a
= Gm²/a [4 + √2]
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