Question

Four particles each of mass m are placed at the corner of a square of side 'a' each. Find force acting on one of the particles due to other particles.​

Answer 1

Answer:

According to pythagors theorem

In △ACD

(AC)2=(AD)2+(DC)2

⇒ (AC)2=a2+a2

⇒ Ac=a2

Now,

we know that

F=r2Gm1m2 [gravitational force]

⇒ FAB=a2Gm×m=a2Gm2

FAD=a2Gm2

FAC=(AC)2Gm2=2a2Gm2

Fnet=(FAB2+(FAD2))

=(a2Gm2)2+(a2Gm2)2

⇒ Fnet=2a2Gm2

tanθ=FADFAB

⇒ tanθ=1

⇒ θ=45o

hence

Fnet and FCD is in same

direction.

⇒ Net force on particle A=Fnet+FCD

2a2Gm2+2a2Gm2

=a2Gm2[2+21]

=2a2Gm2(2+1)

Explanation:

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