Question

four particles of masses m, 2m, 3m, 4m respectively are placed at the corners of a square of side a, as shown in fig​

Answer 1

Answer:

Answer

Let co-ordinates of center of mass is M(x,y).

x=

m

1

+m

2

+m

3

+m

4

m

1

x

1

+m

2

x

2

+m

3

x

3

+m

4

x

4

=

m+4m+3m+2m

m×0+(4×0+3×a+2×a)m

=

10m

5am

=

2

1

a

y=

10m

m×0+4m×a+3m×a+2m×0

=

10m

7am

=

10

7

a

M(

2

1

a,

10

7

a)