Question

four particles of masses m, m, 2m&2m are placed at the four corners of a square of side a find the center of mass the system​

Answer 1

Answer:

(a/2, 2a/3)

Explanation:

$x_{com} = \frac{m1x1+m2x2+m3x3+m4x4}{m1+m2+m3+m4}$

$x_{com} = \frac{m*0+m*a+2m*a+2m*0 }{m+m+2m+2m}$

$x_{com} = a/2$

$y_{com} = \frac{m*0+m*0+2m*a+2m*a}{m+m+2m+2m}$

$y_{com} = 2a/3$

Coordinates are (a/2, 2a/3)

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