Question

Four people a, b, c and d of masses 7,9,5 and 13 ( in kg) respectively are moving with their respective velocities in the ratio 4:3:5:2. Who will have the highest momentum

Answer 1

Answer:

person A has maximum momentum

Step-by-step explanation:

momentum for A= 7×4= 28 kgm/s

momentum for B=9×3= 27

momentum for c= 5×5=25

momentum for D= 13×2=26

Answer 2

Answer:

The people moving with velocity 4 x m/s will have highest momentum.

Step-by-step explanation:

We are given that four peoples a, b, c and d of masses 7 Kg,9 Kg,5 Kgand 13 Kg.

The ratio of their  velocities is 4:3:5:2

Let x be the quantity that is multiplied with each term of ratio.

The velocity of first people=4 x m/s

The velocity of second people= 3 x m/s

The velocity of third people= 5 x m/s

The velocity of fourth people= 2 x m/s

Mass of first people=7 Kg

Mass of second people=9 Kg

Mass of third people= 5 Kg

Mass of fourth people= 13 Kg

We have to find the  people  have  highest momentum.

Momentum ,p= $mass \times velocity$

Momentum of first people= $7\times 4x=28 x Kg m/s$

Momentum of second people=$9\times 3x=27 x Kg m/s$

Momentum of third people=$5\times 5x=25 x Kg m/s$

Momentum of fourth people=$13\times 2 x=26 xKg m/s$

The momentum of first people is greatest. Hence, the first people has highest momentum.

The people moving with velocity 4 x m/s will have highest momentum.