Question

four people a b c and d of masses 795 and 13 in KG respectively are are moving their with their respective velocities in the ratio 4:3:5:2.who will have the highest momentum ​

Answer 1

Answer:

a has the highest momentum

Explanation:

Let the common ratio of the velocities be v m/s

Then

The velocity of a = 4v m/s

Velocity of b = 3v m/s

Velocity of c = 5v m/s

Velocity of d = 2v m/s

Given the masses of a, b, c, d respectively are 7, 9, 5 and 13 kg

We know that

Momentum = Mass × Velocity

Therefore,

Momentum of a = 7 × 4v = 28v kg-m/s

Momentum of b = 9 × 3v = 27v kg-m/s

Momentum of c = 5 × 5v = 25v kg-m/s

Momentum of d = 13 × 2v = 26v kg-m/s

From the above calculated momentums, it is clear that a has the highest momentum