Math, asked by payash8334, 11 months ago

Four people A,B,C,D of masses 7,9,5,13 respectively are moving with their respective velocities in the ratio 4:3:5:2.who will have the highest momentum

Answers

Answered by bhatiamona
4

Answer:

A with mass 7

Step-by-step explanation:

Given,

people with mass

A= 7

B= 9

C= 5

D= 13

velocities of A, B, C, D is in ratio

4:3:5:2

Let x be factor

then,

Velocity of A= 4x

Velocity of B= 3x

Velocity of C= 5x

Velocity of D= 2x

Momentum = mass x velocity

i.e. p= mv

Momentum of A= 7×4x= 28x

Momentum of B= 9×3x= 27x

Momentum of C= 5×5x= 25x

Momentum of D= 13×2x= 26x

Here we can see that Momentum of A is highest i.e. 28x

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