Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?
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11x+9x+6x+14x=176
= 40x= 176
then x=4.4
11× 4.4=48.4
9×4.4=39.6
6×4.4=26.4
14×4.4=61.6
then the youngest is C and eldest is D
= 40x= 176
then x=4.4
11× 4.4=48.4
9×4.4=39.6
6×4.4=26.4
14×4.4=61.6
then the youngest is C and eldest is D
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