Math, asked by ds28april, 1 year ago

Four persons A,B,C and D share their prize amount of Rs. 1,00,000 in such a way that four times the A's, three times the B's, two times the C's and D's prize shares are equal. The sum of prize amounts of A and D is :​

Answers

Answered by amitnrw
4

Answer:

Four persons A,B,C and D share their prize amount of Rs. 1,00,000 in such a way that four times the A's, three times the B's, two times the C's and D's prize shares are equal. The sum of prize amounts of A and D is :​ Rs 60000

Step-by-step explanation:

4A = 3B = 2C = D

=> A = D/4

=> B = D/3

=> C = D/2

Let say D Share = 12S  Rs

C Sharea = 12S/2 = 6S  Rs

B Share = 12S/3 = 4S     Rs

A Share = 12S/4 = 3S      Rs

Total Share = 12S + 6S + 4S + 3S = 25S   Rs

25S = 100000

=> S = 4000

A + D = 3S + 12S = 15S

A + D Amount = 15 * 4000 = Rs 60000

Answered by qwtiger
2

Answer:

Rs. 60,000

Step-by-step explanation:

From the conditions given n the question, the following equation can be concluded:

4A = 3B = 2C = D

Let's take D as independent and assume that he shares 12K Rs.(Herewe have taken 12 because it is the LCM of 4,3 and 2)

According to (1) C shares 6k

B shares 4k and A shares 3K Rupees.

Total = 12k + 6k + 4k + 3k = 25k

25k = 100000

k = 4000

Total amount of A and D = 12k + 3k =15k

15*4000 = 60000

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