Math, asked by ds28april, 11 months ago

Four persons A,B,C and D share their prize amount of Rs. 1,00,000 in such a way that four times the A's, three times the B's, two times the C's and D's prize shares are equal. the sum of prize amounts of A and D is :​

Answers

Answered by jpc2005
2

Ok let's think they are in ratio:4A:3B:2C:D=X

so A=X/4 ,B=X/3 ,C=X/2 ,D=X

Now Lcm of 4,3,2,and 0 =12

so A=3X B=4X c=6X D=12X

So they are in ratio 3X:4X:6X:12X

Now all X will cut down

so now ratio is 3:4:6:12

SO THEY ARE A:B:C:D

so a+b+c+d = rupees 100000

so 25=100000

1=100000/25=4000

so A = 4000*3=12000

B=4000*4=16000

C=4000*6=24000

D=4000*12=48000

Now A+B+C+D=Rupees 100000

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