four persons are chosen from a group continuing 3 men , 2 women and 4 children. show that the chance that exactly two of them will be children is 10/21. plz answer
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chance of exactly 2 children is
(4C2 × 5C2)/9C4.
{(4×3/2)×(5×4/2)}/9×2×7
6×10/21×6
10/21
on solving,u will get the answer
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(4C2 × 5C2)/9C4.
{(4×3/2)×(5×4/2)}/9×2×7
6×10/21×6
10/21
on solving,u will get the answer
hope u like it
plz follow me
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