Physics, asked by wardhanharsh764, 5 months ago

four point charge each of magnitude q are placed at the vertices of the square of side a find the electric potential at the distance r from it's center and making an 45 degree​

Answers

Answered by abhisingh76
0

Answer:

•Let r be the distance of each charge from center of the square ,

then r

2

+r

2

=D

2

,

or r=D/

2

,

q

electric potential at he center of square due to four charges , each of +Q at the four corners ,

V=k(Q/r+Q/r+Q/r+Q/r) ,

or V=k(4Q)/r=4kQ/(D/

2

) ,

or V=4KQ/(Dcos45

o

) (because cos45

0

=1/

2)

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