four point charge each of magnitude q are placed at the vertices of the square of side a find the electric potential at the distance r from it's center and making an 45 degree
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Answer:
•Let r be the distance of each charge from center of the square ,
then r
2
+r
2
=D
2
,
or r=D/
2
,
q
electric potential at he center of square due to four charges , each of +Q at the four corners ,
V=k(Q/r+Q/r+Q/r+Q/r) ,
or V=k(4Q)/r=4kQ/(D/
2
) ,
or V=4KQ/(Dcos45
o
) (because cos45
0
=1/
2)
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