Four point charges 1 µC, -2 µC, 3 µC and -2 µC are placed at the four vertices of a square of side 1 cm The dipole moment of this charge assembly is
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Explanation:
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Answer:
0
Explanation:
The given figure shows a square of side 10 cm with four charges placed at its corners. O is the centre of the square.
Where, (Sides) AB = BC = CD = AD = 10 cm (Diagonals)
AC = BD = 10√2 cm AO = OC = DO = OB = 5√2 cm
A charge of amount 1μC is placed at point O. Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O. Hence, they will cancel each other. Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O. Hence, they will also cancel each other. Therefore, net force caused by the four charges placed at the corner of the square on 1 μC charge at centre O is zero