Question

Four point charges of charge 1 μC each are placed at four corners of a square of side 2 m. The work done in removing a charge -2 μC from centre of square to infinity is

1.28 J

19.61 J

50.9 mJ

4.83 J​

Answer 1

Answer:

1.28 is a correct answer .

Answer 2

Answer:

The work done in removing a charge -2 μC from centre of square to infinity is 50.9mJ

Explanation:

Given : $q=-2\mu C$; side = 2m

Work done in removing a charge from a system is =$q\Delta V$

Potential at the center of the square = $\frac{K Q}{l} +\frac{K Q}{l} +\frac{K Q}{l} +\frac{K Q}{l} =4\frac{K Q}{l}$

where, $l$ is the distance of each charge at corner from center = $\frac{2}{\sqrt{2} }=\sqrt{2}$

Potential at infinity = 0

The work done in removing a charge -2 μC from centre of square to infinity is W = $q\Delta V=q(V_c-V_{\infty})= q\frac{4KQ}{l} =q\frac{4KQ}{\sqrt{2} }$

Calculation:

W= $-2*10^{-6} * \frac{4*9*10^9*(10^{-6})}{\sqrt{2} } =50.9mJ$

The work done in removing a charge -2 μC from centre of square to infinity is 50.9mJ.

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