Four point charges q = 2 C, Q B = -5 C, Q = 2 C, Q = 5 C are located at the corners of a square ABCD of side of 10 cm. What is the force on a charge of 1 C placed at the centre of the square
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Answer:
1.8×10^9
Explanation:
2C s are in opposite corners of square. so,their forces canceled each other. and the rest
one attractive and other repulsive..and along one direction.
so,F= 2×(1/4 pi Eo)(1×5/25×2)
= (2×9×10^9×5)/50
=1.8×10^9
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