Physics, asked by madhuaras9, 15 days ago

Four point charges q₁ = 3 nC, qв = -3 nC and qc = 3 nC, are located at the corners A,B and C of a square ABCD of side 12 cm. What is the force on a charge of 2μC placed at corner D?​

Answers

Answered by pathanayan57305
0

Answer:

The given figure shows a square of side 10 cm with four charges placed at its corners. O is the centre of the square.

Where,

(Sides) AB=BC=CD=AD=10cm

(Diagonals) AC=BD=10

2

cm

AO=OC=DO=OB=5

2

cm

A charge of amount 1μC is placed at point O.

Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O. Hence, they will cancel each other. Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O. Hence, they will also cancel each other. Therefore, net force caused by the four charges placed at the corner of the square on 1μC charge at centre O is zero.

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