Four point charges qA = 2 μC, qB = –5 μC, qC = 2 μC, and qD = –5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?
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The charges of equal magnitude and same sign are at the corners of same diagonal. So they will exhibit equal and opposite forces at the charge situated at center, cancelling out each other. So, the force is zero Newton.
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Hello friends.
Four Charges are placed at corners of square of side length 10cm and a charge is placed at centre(O) of square as shown in figure.
forces of repulsion on 1μC charge at O due to 2μC charge at A and C are equal and opposite directions .
e.g.,
Therefore, these are cancelled.
Similarly, forces of attraction on 1μC charge at O , due to -5μC charges at B and at D are equal in magnitude and opposite in directions.
e.g.,
Therefore, these are also cancelled.
Hence, the net force on the charge of 1μC at O is zero.
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