Four point masses each of mass m are kept at the vertices of a square. a point mass m is kept at the point of intersection of the diagonal of a square.What will be the force experienced by center mass m?
Answers
The net force experienced by the center mass will be ZERO
The center particle will experience force of attraction from all the the four particle aat the 4 vertices.
Let us assume a square ABCD with diagonal AC and BD and center o.
considering diagonal AC the center point will experience equal and opposite force from point A and C because the mass and distance are equal. So they will cancel out each other.
Similarly the force of attraction from point B and D will cancel out each other.
Hence the net force of experienced will be zero.
Answer:
ZERO
Explanation:
Let the square is ABCD and its centre (intersecting point is O) then the centre is equidistant from all corners. So the magnitude of force due to mass at each corner on the mass at centre is same.
From the figure we can observe that,
FOA & FOD are opposite to each otherandFOB & FOC are opposite to each other
So the net force on the mass m at the centre becomes zero.
