Four point masses of 2 kg placed at 4 corners of a square of side 1m. Find net gravitational force acting on any of mass is
Answers
Answer:
8 is answer
Explanation:
because
2×4=8
The formula
Answer: The net gravitational force acting on any of the four-point masses of 2 kg placed at the corners of a square of side 1m is
4.151 x 10^-10 N.
To find the net gravitational force acting on one of the point masses, we need to calculate the gravitational force due to each of the other three masses and then add them up vectorially.
Let's assume that the mass we are interested in is located at one corner of the square, and the other three masses are located at the other three corners of the square.
The distance between each of the masses is the diagonal of the square, which is sqrt(2) times the side length. So the distance between the two masses is 1.414 m.
Using Newton's Law of Universal Gravitation, the gravitational force between two masses m1 and m2 separated by a distance r is given by:
F = G * (m1 * m2) / r^2
where G is the gravitational constant, which has a value of approximately
So the magnitude of the gravitational force between one of the point masses of 2 kg and each of the other three masses is:
Since the three masses are symmetrically placed with respect to the mass of interest, the direction of each of the gravitational forces will be along a diagonal of the square and will have the same magnitude.
Therefore, the net gravitational force acting on the mass of interest will be the vector sum of the gravitational forces due to the other three masses. Since the forces are all acting along diagonals of the square, we can use the Pythagorean theorem to add them up vectorially.
The net gravitational force will be:
So the net gravitational force acting on any of the four-point masses of 2 kg placed at the corners of a square of side 1m is 4.151 x 10^-10 N.
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