Question

Four point size bodies each mass M are fixed at four corners of a light square frame of corner length L. the moment of inertia of four bodies about an axis passing through opposite corners of frame is ​

Answer 1

Answer:

ML^2  will be the moment of inertia of every mass m.

Explanation:

formula to calculate the moment of inertia is mass multiply with the sqr of perpendicular distance to the rotation axis.

in this case the mass of a body is M and perpendicular distance is equal to the length of frame. as all bodies are at the corners of the frame

so Moment of inertia will be = mass * (frame length) ^ 2

for all bodies it will be 4 times.