Question

Four point size bodies each of mass M are fixed at four corners of a light
square frame of corner length L. The moment of inertia of four bodies
about an axis perpendicular to the plane of frame and passing through a
corner is​

Answer 1

Answer:2ml^2

Explanation:

Answer 2

Answer:

2ML^2.

Explanation:

Since, the length of the sides of the square frame is given as L so the diameter d will be L√2. So, the distance from the center to any corner will be d/2 which we take as x. So, it will be 2x = L√2 which on solving we will get that the x=l/√2.

So, now the moment of inertia of the axis passing perpendicular through a corner will be given as Mx^2 which will be 4m*(l/√2)^2. Which on solving we will get that 2ML^2.