Four point size bodies each of mass
m are fixed at four corners of
light square frame of side length 1m.
The radius of gyration of these four
bodies about an axis perpendicular
to the plane of frame passing
through its centre is
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Answered by
0
Answer:
I don't know about this question
Explanation:
and thank-you for Free point
Answered by
3
Answer:
I=4(m(
2
L
)
2
)
=2mL
2
So we have radius of gyration equivalence equation as,
4mk
2
=2mL
2
k=
2
L
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