Four points charges qa= 2 uc , qb = -5 uc , qc = 2 uc and qd = -5 uc are located at the corners of the square abcd of side 10 cm . what is the force on a charge of 2 uc placed at the centre of the square.
Answers
net force on 2 μc at the centre of the square. is Zero
Explanation:
its a square
Center of the square is at equal distance from each vertex
F = kq₁q₂/r²
Same charges repel
& opposite charges attract
qa= 2 μc
qc= 2 μc
are two charges of same magnitude at diagonally opposite vertex
Hence force by them at 2 μc on center will of of same magnitude but in opposite direction
Hence cancel out each other
qb= -5 μc
qd= -5 μc
are two charges of same magnitude at diagonally opposite vertex
Hence force by them at 2 μc on center will of of same magnitude but in opposite direction
Hence cancel out each other
So net force on 2 μc at the centre of the square. is Zero
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