Four prime numbers are written in ascending order of their magnitudes. The product
of first three is 715 and that of last three is 2431. What is the largest given prime
number?
Answers
Answered by
2
Answer:
17
Step-by-step explanation:
let a<b<c<d are the primes
a×b×c = 715
b×c×d = 2431
now b×c×d/a×b×c = 2431/715
d/a = 11×13×17/5×11×13
d/a = 17/5
largest prime (d) = 17
smallest prime (a) = 5
Answered by
2
Answer:
17
Step-by-step explanation:
let a‹b‹c‹d are the primes
a×b×c=715
b×c×d=243
now b× c ×d /a× b×c=2431/715
d/a=11×13×17×/5×11×13
d/a=17/5
largest prime(d)=17
smallest prime (a)=5
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