Math, asked by Anonymous, 11 months ago

Four prime numbers are written in ascending order of their magnitudes. The product
of first three is 715 and that of last three is 2431. What is the largest given prime
number?​

Answers

Answered by hrn21agmailcom
2

Answer:

17

Step-by-step explanation:

let a<b<c<d are the primes

a×b×c = 715

b×c×d = 2431

now b×c×d/a×b×c = 2431/715

d/a = 11×13×17/5×11×13

d/a = 17/5

largest prime (d) = 17

smallest prime (a) = 5

Answered by sarikakhajotiya
2

Answer:

17

Step-by-step explanation:

let a‹b‹c‹d are the primes

a×b×c=715

b×c×d=243

now b× c ×d /a× b×c=2431/715

d/a=11×13×17×/5×11×13

d/a=17/5

largest prime(d)=17

smallest prime (a)=5

Similar questions