Question

Four quids A, B, C & D have boiling point of 320 K , 100 degree centigrade, 75 degree centigrade and 370 K respectively. Which liquid will have maximum rate of evaporation at 25 degree centigrade temperature.

Answer 1

Answer:

Liquid A boiling point = 320 K = 320 - 273 = 47°C

Liquid B boiling point = 100°C

Liquid C boiling point = 75°C

Liquid D boiling point = 370 K = 370 - 273 = 97°C

The lowest boiling point is of Liquid A.

The maximum rate of evaporation at 25°C is of Liquid A.

As Liquid A has lowest boiling point than other Liquids it will heat up and boil and also will start evaporating faster than other liquids.

Extra Information:

Relationship between Kelvin Scale and Celsius Scale Temperature is as follows :-

Temperature on Kelvin Scale =  Temperature on Celsius Scale + 273

Temperature on Celsius Scale = Temperature on Kelvin Scale - 273

[Note => We take rounding off as 273 K for conversion or else to be precise it is 273.15 K]

Answer 2

$\underline{\underline{\huge{\green{\tt{\textbf Answer:- }}}}}$

✰Liquid A boiling point = 320 K = 320 - 273 = 47°C

✰Liquid B boiling point = 100°C

✰Liquid C boiling point = 75°C

✰Liquid D boiling point = 370 K = 370 - 273 = 97°C

✰The lowest boiling point is of Liquid A.

✰The maximum rate of evaporation at 25°C is of Liquid A.

✭As Liquid A has lowest boiling point than other Liquids it will heat up and boil and also will start evaporating faster than other liquids.

[Note => We take rounding off as 273 K for conversion or else to be precise it is 273.15 K]☄

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