Question

four resistance 1 ohm 2 ohm 3 ohm 4ohm are connected in series with a battery of 12 volt as shown calculate the current and the potential difference across ends of each resistance​

Answer 1

V=12V

R=1+2+3+4=10ohm( SINCE THEY ARE IN SERIES)

V=IR

12=I×10

12/10=I

1.2A=I

THE V AT 1ohm resistance

V=IR

V=1.2×1

V=1.2V

SIMILARLY THE NEXT RESISTANCES ARE 2.4 3.6 4.8 ohm

HOPE THAT THIS WILL HELP YOU OUT ✔✔