Four resistance of 2 Ohm each are joined to form a square ABCD. Calculate the equivalent resistance of the combination between any two adjacent corners.
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Answered by
120
When wires are joined at two adjacent corners, then three consecutive resistors let R1, R2 and R3 are in series.
Therefore, equivalent resistance in series = Rs = R1+R2+R3
= 2+2+2 = 6 ohm.
Now, Rs is in parallel with fourth resistor that is R4.
Final equivalent resistance= 1/Rp= 1/Rs+1/R4 =2/3
Therefore, RP = 1.5 ohm.
Therefore, equivalent resistance in series = Rs = R1+R2+R3
= 2+2+2 = 6 ohm.
Now, Rs is in parallel with fourth resistor that is R4.
Final equivalent resistance= 1/Rp= 1/Rs+1/R4 =2/3
Therefore, RP = 1.5 ohm.
Answered by
48
Rs=2ohm+2ohm+2ohm=6ohm
1/Rp=1/6+1/2
2x1+6x1/12
2+6/12
8/12ohm=1/Rp
Rp=12/8=1.5ohm
I hope this will help you
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