Question

Four resistance of 24 o 12ohm8ohm4ohm are connected in parallel.calculate the total resistance of the circuit

Answer 1

Answer:

Given information:

Resistance 1

$r 1 = 24ohm$

Resistance 2

$r2 = 12ohm$

resistance 3

$r3 = 8 \: ohm$

resistance 3

$r4 = 4ohm$

the equivalent resistance in parallel connection is given as,

$\frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} + \frac{1}{r4}$

substituting all known values,

$\frac{1}{r} = \frac{1}{24} + \frac{1}{12} + \frac{1}{8} + \frac{1}{4} \\ \frac{1}{r} = \frac{1}{2}$

taking reciprocal,

$r = 0.5 \: ohm$

therefore, the equivalent resistance of the resistors in parallel combination is 0.5 ohm