Four resistances 4, 4, 4 and 12 ohams form a
Wheatstone's network. Find the resistance
which when connected across the
12ohams resistance, will balance the network.
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Wheatstone bridge condition:
R1/R2 = R3/R4
R1=4,R2=4,R3=4 ,R4= (12x/12+x)
4/4=4/(12x/12+x)
12X/12+X=4
12X=36+4X
8X=36
X=9
9 ohms resistance must be connected in parallel with 12 ohms
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