Question

Four resistances of 12 ohms 15 ohm 10 Ohm and 4 ohm respectively are connected in cyclic order to form wheatstones network. Is the network balanced? if not calculate the resistance to be connected in parallel with the resistance of 10 Ohm to balance the network.

Answer 1

Answer:

parallel,

M/A=10R/10+R

For balanced wheatstone bridge,

15/12=10R/10+R/4

15/12=10R/4(10+R)

15/12=10R/40+4R

15(40+4R) =12*10R

600+60R=120R

600=120R-60R

600=60R

R=600/60

R=10 ohm

Bridge is not balanced