Question

four resistances of 2ohm are connected on the sides of a square. calculate the equivalent resistance of combination between diagonally opposite corners?​

Answer 1

Explanation:

The diagram indicates a square ABCD formed by joining four resistances of 2Ω each, end to end.

Let us calculate the equivalent resistance of the combination B between the two adjacent comets C and D.

From figure, arms DA, AB and BC are joined in series.

So, their equivalent resistance = (2 + 2 + 2)Ω = 6Ω

Now resistance of 6Ω and 2Ω are in parallel.

∴ The equivalent resistance of the combination is R

Then, 1/R = 1/6 + ½ = 4/6 = 2/3

∴ R = 3/2Ω

= 1.5Ω

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