Physics, asked by shakatikrupa, 5 months ago

four resistors 5Ω,6Ω,4Ω and 8Ω r connect head in 1.series 2. parallel find the equivalent resistance in each case.​

Answers

Answered by yashsingh8704
1

Answer:

Explanation:

In series connection R  

n

​  

=R  

1

​  

+R  

2

​  

+R  

3

​  

+R  

4

​  

=5+6+4+8=23Ω

In the parallel connection  

R  

n

​  

 

1

​  

=  

5

1

​  

+  

6

1

​  

+  

4

1

​  

+  

8

1

​  

=0.74Ω  

−1

 

R  

n

​  

=1.34Ω

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