Question

four resistors 5 ohm 6 ohm 4ohm &8ohm are connected in parallel .find the equivalent resistance in each case​

Answer 1

Answer:

1.411 ohms

Explanation:

In parallel

Equivalent resistance=

1/Re=1/5+1/6+1/4+1/8

1/Re=85/120

Re=120/85

Re=1.411 ohms

Answer 2

The equivalent resistance in each case is 1.34 ohms.

Explanation:

Resistor 1, $R_1=5\ \Omega$

Resistor 2, $R_2=6\ \Omega$

Resistor 3, $R_3=4\ \Omega$

Resistor 2, $R_4=8\ \Omega$

We need to find the equivalent resistance in this case. We know that the equivalent resistance in parallel combination is given by :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}$

$\dfrac{1}{R}=\dfrac{1}{5}+\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{8}\\\\R=1.34\ \Omega$

So, the equivalent resistance in each case is 1.34 ohms. Hence, this is the required solution.

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