Question

Four resistors of resistance 0.5ohm, 1.5 ohm 4 ohm and 6 ohm areconnected in series to a
battery of e.m.f. 6 Vand
negligible internal resistance.
Calculate 1. current drawn
from the cell 2. p.d. at the ends
of 1.5 ohm resistor.
*​

Answer 1

Total resistance R = 0.5+1.5+4+6 = 12 ohm

V = 6V

1. V= iR

i = V/R = 6/12 = 0.5 A

2. pd across 1.5 ohm will be V= 0.5 *1.5 = 0.75 V