four solid spheres each of diameter a and mass m are placed with their centres on the four corners of a square of side b find the moment of inertia about one side of square?
Anonymous:
what is length of side of square...?
it is given in the question square of side b
ok..
is answer 2Ma^2/5 + Mb^2...?
Answers
Answered by
3
HI,
THE Chapter:- System of Particles and Rotational Motion
YOUR ANSWER,
________________________________
M.I of 1,4 spheres about AB=2 [2/5 Ma^2]
M.2 of 2,5 spheres about BC=2 [2/5 Ma ^2]
2,3 spheres about AB= 4/5Ma^2 + 2Mb^2
Therefore,
Inertia
=8/5Ma^2 +2Mb^2
_______________
HOPE THIS HAS CLEARED YOUR DOUBT :-)
THE Chapter:- System of Particles and Rotational Motion
YOUR ANSWER,
________________________________
M.I of 1,4 spheres about AB=2 [2/5 Ma^2]
M.2 of 2,5 spheres about BC=2 [2/5 Ma ^2]
2,3 spheres about AB= 4/5Ma^2 + 2Mb^2
Therefore,
Inertia
=8/5Ma^2 +2Mb^2
_______________
HOPE THIS HAS CLEARED YOUR DOUBT :-)
many many thanks for the answering the question
np
Answered by
14
Hi...!!!
Here is your answer...
Sorry for bad handwriting and corrections....
Hope this helps you....
Here is your answer...
Sorry for bad handwriting and corrections....
Hope this helps you....
Attachments:
writing doesn't matter
hmm..
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