Question

Four Solutions of πx+y=8​

Answer 1

Ans.

πx+y=8

(i) If x=0

π×0+y=8

0+y=8

y=8

(ii)If y=0

πx+0=8

πx=8

(iii)If x=1

π×1+y=8

π+y=8

πy=8

(iv) If y=1

πx+1=8

πx=8-1

πx=7

Answer 2

Question :-

Four Solutions of πx+y=8.

Solution :-

Given Equation :

• πx + y = 8

Need to find :

• Four Solution of that equation

1) Substitute x = 0

$\sf:\longmapsto{\pi(0) + y = 8} \\ \\ \sf:\longmapsto{y = 8} \: \: \: \: \: \: \: \: \: \: \: \:$

2) Substitute y = 0

$\sf:\longmapsto{\pi x + 0= 8} \\ \\ \sf:\longmapsto{\pi x= 8} \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{x = \frac{8}{\pi} } \: \: \: \: \: \: \:$

3) Substitute x = 1

$\sf:\longmapsto{\pi(1) + y = 8} \\ \\ \sf:\longmapsto{\pi + y = 8} \: \: \: \: \\ \\ \sf:\longmapsto{y = 8 - \pi} \: \: \:$

4) Substitute y = 1

$\sf:\longmapsto{\pi x + 1 = 8} \\ \\ \sf:\longmapsto{\pi x = 8 - 1} \\ \\ \sf:\longmapsto{}\pi x = 7 \: \: \: \: \: \: \\ \\ \sf:\longmapsto{x = \frac{7}{\pi} } \: \: \: \:$

The four Solution of πx + y = 8

$\sf:\longmapsto{(0,8)} \: \: \: \: \: \: \: \: \\ \\\sf:\longmapsto{ \bigg( \frac{8}{\pi} ,0 \bigg)} \: \: \: \: \\ \\ \sf:\longmapsto{(1,8 - \pi)} \\ \\ \sf:\longmapsto{ \bigg ( \frac{7}{\pi} , 1\bigg)} \: \: \:$

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