Four spheres each of mass M and diameter 2a are placed at the corners of square of side b as shown below Calculate the moment of inertia ab
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Moment of Inertia (MOI) of sphere about centre of mass =
52Ma 2
Using parallel axis theorem, I=I
cm+Mx2
, Where I cm
In MOI about centre of mass and x is distance between centre of mass and axis of rotation.
⇒ MOI of system about one side of the square =2( 52 Ma 2)+2( 52Ma 2+M )= 58
So,
Ma 2+2Mb 2
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