Question

Four spheres each of mass m and radius r with their centres at four corners of a square of side l

Answer 1

Answer:

Moment of inertia for 4 spheres =

4(2/5mr2)

Since two of them are at a distance a from axis

We add 2(ma2)

So final m.o.i

4(2/5mr2) + 2(ma2)

=8/5mr2 + 2ma2

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Feel free to ask for any clarifications

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