Chemistry, asked by JasonR7861, 11 months ago

Four students added a small amount of ethanoic acid to sodium hydrogencarbonate. The gas evolved was tested for its behaviour with burning splinter and lime water. They reported their observations as given below.
Student
Gas evolved
Action on burning splinter
Action on lime water
A
CO2
The flame of splinter extinguishes and gas does not burn
Turned milky
B
SO2
The splinter burns brightly and the gas burns with a pop
Turned green
C
NO2
The gas does not burn but the splinter burns with a hissing sound
Turned black
D
O2
The gas burns with a yellow flame and the splinter extinguishes
Turned purple
The correct observations have been reported by student
(1) A
(2) B
(3) C
(4) D

Answers

Answered by jasleenkaurever
2

Answer:

(1). A because

CH3COOH+NaHCO3-----CH3COONa+H2O+CO2

Answered by shilpa85475
0

Explanation:

CH₃COOH (aq) + NaHCO₃ (aq) → CH₃COONa (s) + H₂O (l) + CO₂ (g)

When acetic acid or ethanoic acid is added to the sodium hydrogen carbonate, it produces sodium acetate i.e., sodium carboxylate salt and a carbonate product which is obtained due to the formation of carbon dioxide that is responsible to turn the lime water into milky form. Along with the carbonate compound, it gives water.

Therefore, Student A’s observations are correct.

You can get all the answers of Chapter 6 in the link below:

https://brainly.in/question/15022299

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